Talk:Tenerence Love
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Anyone think he looks like Suge Knight? Compare Love to Knight. Homsar999 23:06, 2 January 2008 (UTC)
[edit] Rabbit Algebra Fun!
According to (Tenerence Love + Tenerence Love)/Tenerence Love = Tenerence Love + 3, Tenerence Love = -1.
- Cool beans unsigned, I was checking to see if someone had calculated that :) — however, The full formula should include "my name is" in the variable declaration. ;) MetaStar 06:48, 21 August 2008 (UTC)
- If assuming the equation is (TL + TL) / TL = TL + 3, then:
- 2TL / TL = TL + 3 {simplifing}
- 2 = TL + 3 {cancel out the unknowns on the left hand side}
- -1 = TL {QED}
- However, if the equation is TL + (TL / TL) = TL + 3, then:
- TL + 1 = TL + 3 {simplifing}
- Since the second equation results in a contradiction where TL cannot be solved (at least, using real numbers), I prefer the first interpretation of the lyrics. Of course, there is a good chance these lyrics aren't supposed to make any sense anyway. – The Chort 14:40, 13 September 2008 (UTC)
Okay, time to settle this.
MNITL + MNITL / MNITL = TL + 3
MNITL + MNITL = TL + 3
2MNITL = TL + 3
-3 -3
TL = 2MNITL - 3
MNITL + MNITL / MNITL = 2MNITL -3 + 3
MNITL + MNITL = 2MNITL - 0
2MNITL = 2MNTL - 0
/2 /2
MNITL = MNITL - 0
-MNITL -MNITL
0 = 0
No solution
Nevermind, I was wrong. It turns out that My Name is Tenerence Love = 2 and Tenerence Love = 0 Cfive 21:13, 25 November 2008 (UTC)
- but i realized something: we've been going about this all wrong all this time (not all of us) b/c that's not what remainder means. it means add the number after the "R" divided by the denominator on the other side of the equation. so, if it's
(MNITL + MNITL) / MNITL = MNITL R3
then that means
(MNITL + MNITL) / MNITL = MNITL + (3 / MNITL)
2MNITL / MNITL = MNITL + (3 / MNITL)
2 = MNITL + (3 / MNITL)
2 - 3/MNITL = MNITL
2MNITL - 3 = MNITL2
MNITL2 - 2MNITL + 3 = 0
factoring this is impossible, so using the quadratic formula, (-b±√(b2-4ac))/2a,
since a = 1, b = -2, c = 3:
(2±√(4-4(1)(3)))/2
(2±√(4-12))/2 =
(2±√-8)/2 =
MNITL = 1±√-2. so no real solutions.
but if it's
MNITL + (MNITL / MNITL) = MNITL R3
then that means
MNITL + (MNITL / MNITL) = MNITL + (3 / MNITL)
MNITL + 1 = MNITL + (3 / MNITL)
1 = 3 / MNITL
MNITL = 3
much easier the second way.
The Knights Who Say Ni 
14:31, 20 August 2009 (UTC)
I recon that (MNITL + MNITL)/ MNITL = MNITL r3 is still being seen in the wrong way. The remainder's like the leftover, and any number plus itself (essentially doubled), then divided by itself has to equal two, so to assign a value to MNITL would be impossible, because there is no value which satisfies the equasion of doulbing a number, then dividing it by the original number which equals anything with remainder 3, as such an equation cannot equal anything other than two.
Also, I don't follow where the guy at the top cancels out unknowns, becuase 2TL / TL = TL + 3
would only simplify on the left by multiplying by the TL, not just getting rid of it, giving us 2TL = TL (squared) +3
So TL (squared) - 2TL +3 = 0
if we assign the following values: a = 1, b= -2, c=3
(the 1 in front of TL squared, the 2 before TL and the 3)
Then find the discriminant (b squared - 4ac) which is: 4 - 4*1*3
we get 4-12 = 8, giving us a discriminant < 0, a disreputable sign that the quadratic has no real solutions, but it could be argued that: (I'm a little sketchy after here)
TL sq -2TL +3 = 0 (completing square)
(TL - 1)sq - 1 +3 =0 = (TL -1)sq -2 =0
therefore (TL -1)sq = -2 and TL -1 = +/- sqrt(-2), so TL = 1 +/- Sqrt(-2), which I believe is expressable as TL = 1+/- 2i, but I'm not sure. Anyway, the point is that you can't have a square root of a negative, further proving that (MNITL+MNITL)/ MNITL = MNITL r3 has not solutions, meaning that (MNITL+MNITL)/MNITL cannot = MNITL r3, and MNITL can thus not have any value whatsoever. Wait, sorry, I was completely wrong, but so were you. I made the mistake of doing 2TL/TL = TL +3 into 2TL = TLsq +3, when it should have been TLsq + 3 TL, but you made the mistake of translating remainder 3 as +3. Lets take 12 divided by nine. It equals 1.3 recurring, or in remainder terms, 1 remainder 3, becuase we get one nine, then 3 left over to get to 12, but that doesn't mean that 12 divided by nine is equal to 1+3, which is four, so although you were entirely correct in solving your own equation, the eqation is question is not related to the problem of (MNITL+MNITL) / MNITL = MNITL r3, because that is not equal to (MNITL+MNITL)/MNITL = MNITL + 3.
Rather, the equation can only be taken at face level: 2MNITL / MNITL = MNITL r 3 (not adding the three this time) => 2 = MNITL r 3, and there's nothing that goes into 2 with 3 left over, because 2 < 3, so that is why the equation is nonsensical. Sorry to have taken so much of your time dilly-dallying.
[edit] Actually singer he may be based on?
I was wondering if he is based on a real person. Could it be Barry White? What about Billy Ocean or Philip Bailey?
And is the melody from "Sweaty Overweight Jam" borrowed from "In Too Deep" by Phil Collins? Boris B 20:57, 4 July 2008 (UTC)
- I still think that he looks like Suge Knight, but maybe that's just me. Homsar999 07:10, 28 November 2008 (UTC)
- I'm fairly sure it's supposed to be Ceelo Green...
- I agree. He's just supposed to be an R&B singer for when the Brothers Chaps need one, he's not a parody of a particular singer. His style is a lot like singers of the late 90s, but he doesn't strike me as being too similar to any one singer. --98.198.38.63 14:21, 4 December 2017 (UTC)
